**Concept: The question tests on basic Geometry**

**Solution:**

Statement I: ∠PRQ = 180 - 40 = 40° Sum of angles on a straight line = 180°

∠PQR = 180 - 100 - 40 = 40°. Sum of angles of a triangle = 180°.

Statement II: ∠PQR = 40°

So ∠PQR = ∠QPS = 40°. Alternate angles between 2 parallel lines cut by a Transversal.

Statement III: ∠PRQ = 40°

So ∠PRQ = ∠RPT = 40°. Alternate angles between 2 parallel lines cut by a Transversal.

All 3 angles = 40°**Option E**