Concept: The question tests on Rates (Time Speed Distance)
Solution:
Let the distance be = d and time be = t
Therefore S1 = d/t
New distance = 2d and new time = t/2
S2 = 2d / (t/2) = 4d/t = 4 * S1
Therefore S1 / S2 = 1 / 4
Option D
Modified on: Tue, 12 Oct, 2021 at 12:49 PM
Concept: The question tests on Rates (Time Speed Distance)
Solution:
Let the distance be = d and time be = t
Therefore S1 = d/t
New distance = 2d and new time = t/2
S2 = 2d / (t/2) = 4d/t = 4 * S1
Therefore S1 / S2 = 1 / 4
Option D
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