**Concept: The question tests on Rates (Time Speed Distance)**

**Solution:**

Let the distance be = d and time be = t

Therefore S1 = d/t

New distance = 2d and new time = t/2

S2 = 2d / (t/2) = 4d/t = 4 * S1

Therefore S1 / S2 = 1 / 4**Option D**

Modified on: Tue, 12 Oct, 2021 at 12:49 PM

**Concept: The question tests on Rates (Time Speed Distance)**

**Solution:**

Let the distance be = d and time be = t

Therefore S1 = d/t

New distance = 2d and new time = t/2

S2 = 2d / (t/2) = 4d/t = 4 * S1

Therefore S1 / S2 = 1 / 4**Option D**

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