Concept: The question tests on Rates (Time Speed Distance)
Solution:
When distance is constant, by the rule of proportionality sA∗tA=sB∗tB
Given that sA= 2 * sB
Therefore 2sB∗3=sB∗tB
time of B = 6 h
Option A
Modified on: Tue, 12 Oct, 2021 at 12:48 PM
Concept: The question tests on Rates (Time Speed Distance)
Solution:
When distance is constant, by the rule of proportionality sA∗tA=sB∗tB
Given that sA= 2 * sB
Therefore 2sB∗3=sB∗tB
time of B = 6 h
Option A
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