Concept: The question tests on the application in Inequality 

Solution:


|x+5|≤|2x−5|

 on squaring both sides:

 x^2  +  10x +  25 ≤    4x^2   − 20x + 25

=>-3x^2 + 30x <=0

=> -x^2 +10x < = 0

Multiply with -1 and flip the sign

=>x^2−10 x ≥ 0
 => x(x−10)≥0  hence the critical points are 0 and 10.

Both are of same sign.

Using the wavy curve approach,  x<=smallest critical point or x>=greatest critical point in this case.

Refer to wavy curve approach explained in the session o Inequality

=>x≤0 or x≥ 10

(option d)