**Concept: The question tests on the area of Number Properties**

**Solution:**

7 cannot be in the units place as that would not be an even number.

The units place can have any of 0, 2, 4, 6 or 8 = 5 numbers

Numbers starting with 57 can end with 0, 2, 4, 6 or 8. In this 5 numbers are possible.

For the remaining numbers the hundreds place can have any 8 numbers (excluding 0 and 5)

Any 9 numbers (excluding 5) can be in the 10's place and the last place will have 5 possibilities

Total such numbers = 8 * 9 * 5 = 360

The total numbers = 5 + 360 = 365

** (option d)**