**Concept: The question tests on the application of Counting**

**Solution:**

The 4 toys can be distributed in 2 , 1, 1 ways where each gets at least 1 toy.

The number of ways of doing this is 4C2 * 2C1 * 1C1 = (4 * 3/2) * 2 * 1 = 12 ways

Now the number of ways where 2,1,1 can be rearranged = 3!/2! = 3 ways (211) (121)(112)

Total ways of distributing the toys = 12 * 3 = 36 ways

For the marbles, since they are the same, let us give away 1 marble to each. We are left with 2 marbles. The number of ways of distributing them is

2, 0, 0 = 3!/2! = 3 ways and

1, 1, 0 = 3!/2! = 3 ways

The total ways = 3 + 3 = 6

Therefore the total distribution can be done in 36 * 6 = 216 ways**Option D**