**Concept: The question tests on the application of Number properties**

**Solution:**

We have that for any number, N broken into prime factors and their powers in the form N=ap∗bq∗crN and so on, then the total number of factors n = (p + 1) * (q + 1) * (r + 1) and so on.

If the number of factors is **even,** then the number of pairs that give the product as N = n2n2

If the number of factors is **odd,** then the number of pairs that give the product as N = n+12n+12

N = 7056 = 2^4∗3^2∗7^2

n = (4 + 1) * (2 + 1) * (2 + 1)

= 5 * 3 * 3 = 45

Therefore the number of pairs = 45+1/2=23

**Option D**