**Concept: The question tests on the area of Modern Math (Counting/Combinatorics)**

**Solution:**

Since books are a finite quantity, they have to be integers and they cannot be negative.**Statement 1:** p3>j2

If p = 2 and j = 1, Then 2^3>1^2 and therefore p > j

If p = 5 and j = 11, Then 5^3>11^2 but p < j

Answer options could be B, C or E** (Insufficient) **

**Statement 2:**j = 3

Answer options could be C or E

**(Insufficient)**

**Combining both statements**

p3>j2 and j = 3. So p3>9

for this p has to be greater than 3 as cubes of 1 and 2 are less than 9.

Both the statements together are sufficient.**(Option C)**