**Concept:** The question tests on the basics of Counting

**Solution**

We can have 4 digit numbers or 5 digit numbers

4 digit numbers: The first place cannot have 3. So we can have 4 numbers in the first place.

Then we can have 4 numbers (including 3 and excluding the number chosen in the first place) in the second place, 3 numbers in the 3 place and any 2 numbers in the last place.

Total numbers possible = 4 * 4 * 3 * 2 = 96

5 digit numbers: All the numbers will be greater than 4000. We can have 5! = 120 numbers

Total numbers greater than 4000 = 96 + 120 = 216 (option a)