**Concept: The question tests on the topic of probability.**

**Solution: **This is a question from the area of Probability.

If we rephrase it, you are asked the probability for obtaining an even sum from numbers 1-20.

An even sum can be obtained in two cases:

(1) Sum of two odd numbers (ex.3+5 = 8 ; 7+5=12 ; 9+13=22) OR (OR is equivalent to addition)

(2) Sum of two even numbers (ex. 4+6=10,8+10=18;12+14=26)

Thus, Probability(Even Sum)

= Prob(1st card is odd AND 2nd card is odd) OR Prob(1st card is even AND 2nd card is even)

= 10/20 x 9/19 + 10/20 x 9/19(As cards are picked simultaneously without replacement, the sample space changes from 20 to 19)

= 1/2 x 9/19 + 1/2 x 9/19

= 9/38 + 9/38

= 18/38

**(option d)**