**CONCEPT: The question uses the concepts of Probability and Counting**

**SOLUTION: **The probability that the second card has the same face value as the first (Implying they both have the same face value) is 3/51,

(As irrespective of what value the first card has, there will be exactly three cards left in the pile of 51 cards, that have that same value.

Probability that the two cards have different values is 1−3/51=48/51=16/17.

Clearly, the chance that the first card has a higher value than the second card is the same as the chance that the second card has a higher value than the first.

So each of them must be (1/2)*16/17 = 8/17 Hence **Option (D)**