Two rectangles have the same area. One is twice as long as the other. If the longer rectangle has a length of L and a width of W, what is the perimeter of the shorter rectangle? : Crackverbal Support

Two rectangles have the same area. One is twice as long as the other. If the longer rectangle has a length of L and a width of W, what is the perimeter of the shorter rectangle? Print

Modified on: Tue, 12 Oct, 2021 at 2:11 PM

SOLUTION:

Rectangle 1(Longer Rectangle):

Length(L1)= L and Width(W1)=W

Rectangle 2: Length(L2) = L/2

Areas being same L*W1 = (L/2)* W2
=>LW=(L/2)*W2
=>W2 = L*W1/(L/2)=2W
Thus Perimeter of the shorter triangle

= 2(Length +Breadth)
= 2(L/2+2W)=L+4W (OPTION D)

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