**CONCEPTS: **The basics of Profit/Loss have been applied in the question.

**SOLUTION:**

A=20$kg, B=24$kg ,C =30$kg

Let x kg be rice A ,y kg be rice B and 2 kg be quantities of rice C

Final CP = 25

Equating the Cost Prices we have-

20x+24y+60=25(x+y+2)

=>y=10−5x

Since, y cannot be zero or negative and for any value of x above 1 we have 0 or negative y

x can only be 1 giving y=5 kg (OPTION C)