SOLUTION:
Let their be A people in group A and B be the number of people in group B.
Thus A+B=50 .....(1)
Also 80A + 90 B =4270 ....(2) (The cost/costume for group A is $80 and for B its $90)
Solving both (1) and (2), we have A=23 and B=27
Thus, cost for group B = 90x27 = $2630 (OPTION E)
A dance troupe has a total of 50 dancers split into 2 groups. The costumes worn by Group A cost $80 each, and those worn by Group B cost $90 each. If the total cost of all the costumes is $4,270, what is the total cost of the costumes worn Print
Modified on: Tue, 12 Oct, 2021 at 12:14 PM
Did you find it helpful? Yes No
Send feedbackSorry we couldn't be helpful. Help us improve this article with your feedback.