SOLUTION:

Let their be A people in group A and B be the number of people in group B.

Thus A+B=50 .....(1)

Also 80A + 90 B =4270 ....(2) (The cost/costume for group A is $80 and for B its $90)

Solving both (1) and (2), we have A=23 and B=27

Thus, cost for group B = 90x27 = $2630 (OPTION E)

## A dance troupe has a total of 50 dancers split into 2 groups. The costumes worn by Group A cost $80 each, and those worn by Group B cost $90 each. If the total cost of all the costumes is $4,270, what is the total cost of the costumes worn Print

Modified on: Tue, 12 Oct, 2021 at 12:14 PM

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