Thus 4x-30=50 and the other angle 2x+10 should also be 50.
The third angle asked =180-(50+50)=80
In triangle ABC, AB = BC. If angle A = (4x – 30)° and angle C = (2x + 10)°, find the number of degrees in angle B. (A) 20 (B) 40 (C) 50 (D) 60 (E) 80 Print
Modified on: Tue, 12 Oct, 2021 at 1:35 PM
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