The Probability of selecting a fair coin= 64/65

The Probability of getting 6 heads in a row with the fair coin= (1/2)^6= 1/64

The Probability of selecting the unfair 2-headed coin= 1/65

Probability of getting 6 heads in a row with the 2-headed coin= 1

If a coin, chosen at random from the bag and then tossed, turns up heads 6 times in a row, the probability that it is the two-headed coin(P (B/A))

= [(1/65)*1] / [{(64/65)*(1/64)}+{(1/65)*1}]

= (1/65)/(2/65)

= 1/2

Hence OPTION (E)[b]

## One coin in a collection of 65 has two heads. The rest are fair. If a coin, chosen at random from the lot and then tossed, turns up heads 6 times in a row, what is the probability that it is the two-headed coin? Print

Modified on: Tue, 12 Oct, 2021 at 3:55 PM

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