Probability that an event A doesn't occur = 1-P(A) where P(A) is the probabiity that A occurs.
The probability that the target is hit by the FIRST shooter only = 0.9 * (1-0.7) * (1-0.5)=0.9*0.3*0.5=0.135
The probability that the target is hit by the SECOND shooter only = (1-0.9)*(0.7)*(1-0.5)=0.1*0.7*0.5=0.035
The probability that the target is hit by the THIRD shooter only =(1-0.9)*(1-0.7)*(0.5) = 0.1*0.3*0.5= 0.015
Hence the probability that the target is hit only by one = 0.135+0.035+0.015 = 0.185 (OPTION B)
Three snipers shoot a certain target. Their probabilities of hitting the target are 0.9, 0.7, and 0.5 respectively. The snipers make one salvo. What is the probability that exactly one sniper hit? Print
Modified on: Tue, 12 Oct, 2021 at 3:54 PM
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