Probability that an event A doesn't occur = 1-P(A) where P(A) is the probabiity that A occurs.

The probability that the target is hit by the FIRST shooter only = 0.9 * (1-0.7) * (1-0.5)=0.9*0.3*0.5=0.135

The probability that the target is hit by the SECOND shooter only = (1-0.9)*(0.7)*(1-0.5)=0.1*0.7*0.5=0.035

The probability that the target is hit by the THIRD shooter only =(1-0.9)*(1-0.7)*(0.5) = 0.1*0.3*0.5= 0.015

Hence the probability that the target is hit only by one = 0.135+0.035+0.015 = 0.185 (OPTION B)

## Three snipers shoot a certain target. Their probabilities of hitting the target are 0.9, 0.7, and 0.5 respectively. The snipers make one salvo. What is the probability that exactly one sniper hit? Print

Modified on: Tue, 12 Oct, 2021 at 3:54 PM

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